In this chapter, we provide RS Aggarwal Solutions for Class 6 Chapter 3 Whole Numbers Exercise 3C for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 6 Chapter 3 Whole Numbers Exercise 3C pdf, free RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Exercise 3C book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 6 |

Subject | Maths |

Chapter | Chapter 3 |

Chapter Name | Whole Numbers |

Exercise | 3C |

Category | RS Aggarwal Solutions |

**RS Aggarwal Class 6 Chapter 3 Whole Numbers Ex 3C Download PDF**

**Question 1.****Solution:**

**Question 2.****Solution:**

**Question 3.****Solution:**

(i) 463 – 9

= 464 – 1 – 9

= 464 – 10

= 454

(ii) 5632 – 99

= 5632 – 100 + 1

= 5633 – 100

= 5533

(iii) 8640 – 999

= 8640 – 1000 + 1

= 8641 – 1000

= 7641

(iv) 13006 – 9999

= 13006 – 10000 + 1

= 13007 – 10000

= 12007

**Question 4.****Solution:**

Smallest number of 7-digits = 1000000

Largest number of 4-digits = 9999

Required difference = (1000000 – 9999)

= 990001

**Question 5.****Solution:**

Deposit in the beginning = Rs. 136000

Next day withdrew = Rs. 73129

Amount left in the bank account = Rs. 136000 – 73129

= Rs. 62871

**Question 6.****Solution:**

Amount withdrawn from the bank = Rs. 1,00,000

Cost of TV set = Rs. 38750

Cost of refrigerator = Rs. 23890

Cost of jewellery = Rs. 35560

Total amount spent on her purchase = Rs. (38750 + 23890 + 35560)

= Rs. 98200

Amount left with her – Rs. 1,00,000 – Rs. 98200

= Rs. 1800

**Question 7.****Solution:**

Population of a town = 110500

Increase in 1 year = 3608

Persons left or died = 8973

The population at the end of year = 110500 + 3608 – 8973

= 114108 – 8973

= 105135

**Question 8.****Solution:**

(i) We have n + 4 = 9

n = 9 – 4 = 5

n = 5

(ii) n + 35 = 101

Subtracting 35 from both sides

n + 35 – 35 = 101 – 35

=> n = 66

n = 66

(iii) n – 18 = 39

Adding 18 to both sides

n – 18 + 18 = 39 + 18

=> n = 57

n = 57

(iv) n – 20568 = 21403 Adding 20568 to both sides

n – 20568 + 20568 = 21403 + 20568

n = 41971

**All Chapter RS Aggarwal Solutions For Class 6 Maths**

—————————————————————————–**All Subject NCERT Exemplar Problems Solutions For Class 6**

**All Subject NCERT Solutions For Class 6**

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